JEE Main 201912 Jan, Evening shiftMathematicsMediumThree Dimensional Geometry249× since 2002If an angle between the line, x+12=y−21=z−3−2{{x + 1} \over 2} = {{y - 2} \over 1} = {{z - 3} \over { - 2}}2x+1=1y−2=−2z−3 and the plane, x−2y−kz=3x - 2y - kz = 3x−2y−kz=3 is cos−1(223),{\cos ^{ - 1}}\left( {{{2\sqrt 2 } \over 3}} \right),cos−1(322), then a value of k is :AOption A. 35\sqrt {{3 \over 5}}53BOption B. −52- {5 \over 2}−25COption C. −32- {3 \over 2}−23DOption D. 53\sqrt {{5 \over 3}}35CheckSkip · show solution