JEE Main 20248 Apr, Evening shiftMathematicsMediumMatrices and Determinants245× since 2002If α≠a,β≠b,γ≠c\alpha \neq \mathrm{a}, \beta \neq \mathrm{b}, \gamma \neq \mathrm{c}α=a,β=b,γ=c and ∣αbcaβcabγ∣=0\left|\begin{array}{lll}\alpha & \mathrm{b} & \mathrm{c} \\ \mathrm{a} & \beta & \mathrm{c} \\ \mathrm{a} & \mathrm{b} & \gamma\end{array}\right|=0αaabβbccγ=0, then aα−a+bβ−b+γγ−c\frac{\mathrm{a}}{\alpha-\mathrm{a}}+\frac{\mathrm{b}}{\beta-\mathrm{b}}+\frac{\gamma}{\gamma-\mathrm{c}}α−aa+β−bb+γ−cγ is equal to :AOption A. 2BOption B. 3COption C. 1DOption D. 0CheckSkip · show solution
