JEE Main 202331 Jan, Evening shiftMathematicsMediumThree Dimensional Geometry249× since 2002If a point P(α,β,γ)\mathrm{P}(\alpha, \beta, \gamma)P(α,β,γ) satisfying (αβγ)(2108938848)=(000)\left( {\matrix{ \alpha & \beta & \gamma \cr } } \right)\left( {\matrix{ 2 & {10} & 8 \cr 9 & 3 & 8 \cr 8 & 4 & 8 \cr } } \right) = \left( {\matrix{ 0 & 0 & 0 \cr } } \right)(αβγ)2981034888=(000) lies on the plane 2x+4y+3z=52 x+4 y+3 z=52x+4y+3z=5, then 6α+9β+7γ6 \alpha+9 \beta+7 \gamma6α+9β+7γ is equal to :AOption A. 115\frac{11}{5}511BOption B. 11COption C. −1-1−1DOption D. 54\frac{5}{4}45CheckSkip · show solution
