JEE Main 202330 Jan, Evening shiftMathematicsMediumThree Dimensional Geometry249× since 2002If a plane passes through the points (−1,k,0),(2,k,−1),(1,1,2)(-1, k, 0),(2, k,-1),(1,1,2)(−1,k,0),(2,k,−1),(1,1,2) and is parallel to the line x−11=2y+12=z+1−1\frac{x-1}{1}=\frac{2 y+1}{2}=\frac{z+1}{-1}1x−1=22y+1=−1z+1, then the value of k2+1(k−1)(k−2)\frac{k^2+1}{(k-1)(k-2)}(k−1)(k−2)k2+1 is :AOption A. 175\frac{17}{5}517BOption B. 613\frac{6}{13}136COption C. 136\frac{13}{6}613DOption D. 517\frac{5}{17}175CheckSkip · show solution
