JEE Main 2003Annual, Paper 1MathematicsEasyMatrices and Determinants245× since 2002If A=[abba]A = \left[ {\matrix{ a & b \cr b & a \cr } } \right]A=[abba] and A2=[αββα]{A^2} = \left[ {\matrix{ \alpha & \beta \cr \beta & \alpha \cr } } \right]A2=[αββα], thenAOption A. α=2ab, β=a2+b2\alpha = 2ab,\,\beta = {a^2} + {b^2}α=2ab,β=a2+b2BOption B. α=a2+b2, β=ab\alpha = {a^2} + {b^2},\,\beta = abα=a2+b2,β=abCOption C. α=a2+b2, β=2ab\alpha = {a^2} + {b^2},\,\beta = 2abα=a2+b2,β=2abDOption D. α=a2+b2, β=a2−b2\alpha = {a^2} + {b^2},\,\beta = {a^2} - {b^2}α=a2+b2,β=a2−b2CheckSkip · show solution
