JEE Main 202126 Aug, Morning shiftMathematicsHardMatrices and Determinants245× since 2002If A=(1525−2515)A = \left( {\matrix{ {{1 \over {\sqrt 5 }}} & {{2 \over {\sqrt 5 }}} \cr {{{ - 2} \over {\sqrt 5 }}} & {{1 \over {\sqrt 5 }}} \cr } } \right)A=(515−25251), B=(10i1)B = \left( {\matrix{ 1 & 0 \cr i & 1 \cr } } \right)B=(1i01), i=−1i = \sqrt { - 1}i=−1, and Q = A^TBA, then the inverse of the matrix A Q²⁰²¹ A^T is equal to :AOption A. (15−2021202115)\left( {\matrix{ {{1 \over {\sqrt 5 }}} & { - 2021} \cr {2021} & {{1 \over {\sqrt 5 }}} \cr } } \right)(512021−202151)BOption B. (10−2021i1)\left( {\matrix{ 1 & 0 \cr { - 2021i} & 1 \cr } } \right)(1−2021i01)COption C. (102021i1)\left( {\matrix{ 1 & 0 \cr {2021i} & 1 \cr } } \right)(12021i01)DOption D. (1−2021i01)\left( {\matrix{ 1 & { - 2021i} \cr 0 & 1 \cr } } \right)(10−2021i1)CheckSkip · show solution
