JEE Main 202117 Mar, Morning shiftMathematicsMediumMatrices and Determinants245× since 2002If A=(0sinαsinα0)A = \left( {\matrix{ 0 & {\sin \alpha } \cr {\sin \alpha } & 0 \cr } } \right)A=(0sinαsinα0) and det(A2−12I)=0\det \left( {{A^2} - {1 \over 2}I} \right) = 0det(A2−21I)=0, then a possible value of α\alphaα is :AOption A. π4{\pi \over 4}4πBOption B. π6{\pi \over 6}6πCOption C. π2{\pi \over 2}2πDOption D. π3{\pi \over 3}3πCheckSkip · show solution
