Differential Equations: JEE Main 2020 Mathematics question

JEE Main 2020 · 2 Sep, Evening shift · Q3604

JEE Main 20202 Sep, Evening shiftMathematicsMediumDifferential Equations163× since 2002

If a curve y = f(x), passing through the point (1, 2), is the solution of the differential equation, 2x²dy= (2xy + y²)dx, then

f\left( {{1 \over 2}} \right)

is equal to :

JEE Main 2020 · 2 Sep, Evening shift · Q3604

JEE Main 20202 Sep, Evening shiftMathematicsMediumDifferential Equations163× since 2002

If a curve y = f(x), passing through the point (1, 2), is the solution of the differential equation, 2x²dy= (2xy + y²)dx, then

f\left( {{1 \over 2}} \right)

is equal to :

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