JEE Main 2004Annual, Paper 1MathematicsMediumCoordinate Geometry478× since 2002If a circle passes through the point (a, b) and cuts the circle x2 + y2=4{x^2}\, + \,{y^2} = 4x2+y2=4 orthogonally, then the locus of its centre is :AOption A. 2ax −2by −(a2 + b2+4)=02ax\, - 2by\, - ({a^2}\, + \,{b^2} + 4) = 02ax−2by−(a2+b2+4)=0BOption B. 2ax +2by −(a2 + b2+4)=02ax\, + 2by\, - ({a^2}\, + \,{b^2} + 4) = 02ax+2by−(a2+b2+4)=0COption C. 2ax −2by +(a2 + b2+4)=02ax\, - 2by\, + ({a^2}\, + \,{b^2} + 4) = 02ax−2by+(a2+b2+4)=0DOption D. 2ax +2by +(a2 + b2+4)=02ax\, + 2by\, + ({a^2}\, + \,{b^2} + 4) = 02ax+2by+(a2+b2+4)=0CheckSkip · show solution
