JEE Main 201610 Apr, Morning shiftMathematicsMediumSequence and Series179× since 2002If A > 0, B > 0 and A + B = π6{\pi \over 6}6π, then the minimum value of tanA + tanB is :AOption A. 3−2\sqrt 3 - \sqrt 23−2BOption B. 2−32 - \sqrt 32−3COption C. 4−234 - 2\sqrt 34−23DOption D. 23{2 \over {\sqrt 3 }}32CheckSkip · show solution