JEE Main 201910 Apr, Morning shiftMathematicsMediumComplex Numbers and Quadratic Equations264× since 2002If a > 0 and z = (1+i)2a−i{{{{\left( {1 + i} \right)}^2}} \over {a - i}}a−i(1+i)2, has magnitude 25\sqrt {{2 \over 5}}52, then z‾\overline zz is equal to :AOption A. −15+35i- {1 \over 5} + {3 \over 5}i−51+53iBOption B. −15−35i- {1 \over 5} - {3 \over 5}i−51−53iCOption C. 15−35i{1 \over 5} - {3 \over 5}i51−53iDOption D. −35−15i- {3 \over 5} - {1 \over 5}i−53−51iCheckSkip · show solution
