JEE Main 201815 Apr, Morning shiftMathematicsHardVector Algebra184× since 2002If a→, b→,\overrightarrow a ,\,\,\overrightarrow b ,a,b, and C→\overrightarrow CC are unit vectors such that a→+2b→+2c→=0→,\overrightarrow a + 2\overrightarrow b + 2\overrightarrow c = \overrightarrow 0 ,a+2b+2c=0, then ∣a→×c→∣\left| {\overrightarrow a \times \overrightarrow c } \right|a×c is equal to :AOption A. 154{{\sqrt {15} } \over 4}415BOption B. 14{{1} \over {4}}41COption C. 1516{{15} \over {16}}1615DOption D. 1516{{\sqrt {15} } \over 16}1615CheckSkip · show solution
