JEE Main 20199 Apr, Evening shiftMathematicsMediumDifferential Equations163× since 2002If cosxdydx−ysinx=6x\cos x{{dy} \over {dx}} - y\sin x = 6xcosxdxdy−ysinx=6x, (0 < x < π2{\pi \over 2}2π) and y(π3)y\left( {{\pi \over 3}} \right)y(3π) = 0 then y(π6)y\left( {{\pi \over 6}} \right)y(6π) is equal to :-AOption A. −π22- {{{\pi ^2}} \over {2 }}−2π2BOption B. −π243- {{{\pi ^2}} \over {4\sqrt 3 }}−43π2COption C. π223{{{\pi ^2}} \over {2\sqrt 3 }}23π2DOption D. −π223- {{{\pi ^2}} \over {2\sqrt 3 }}−23π2CheckSkip · show solution
