JEE Main 202127 Aug, Evening shiftMathematicsEasySequence and Series179× since 2002If 0 < x < 1 and y=12x2+23x3+34x4+....y = {1 \over 2}{x^2} + {2 \over 3}{x^3} + {3 \over 4}{x^4} + ....y=21x2+32x3+43x4+...., then the value of e1 + y at x=12x = {1 \over 2}x=21 is :AOption A. 12e2{1 \over 2}{e^2}21e2BOption B. 2eCOption C. 12e{1 \over 2}\sqrt e21eDOption D. 2e²CheckSkip · show solution
