JEE Main 20169 Apr, Morning shiftChemistryEasyCoordination Compounds198× since 2002Identify the correct trend given below : (Atomic No.=Ti : 22, Cr : 24 and Mo : 42)AOption A. Δ\DeltaΔ^o of [Cr(H₂O)₆]²⁺ > [Mo(H₂O)₆]²⁺ and Δ\DeltaΔ^o of [Ti(H₂O)₆]³⁺ > [Ti(H₂O)₆]²⁺BOption B. Δ\DeltaΔ^o of [Cr(H₂O)₆]²⁺ > [Mo(H₂O)₆]²⁺ and Δ\DeltaΔ^o of [Ti(H₂O)₆]³⁺ < [Ti(H₂O)₆]²⁺COption C. Δ\DeltaΔ^o of [Cr(H₂O)₆]²⁺ < [Mo(H₂O)₆]²⁺ and Δ\DeltaΔ^o of [Ti(H₂O)₆]³⁺ > [Ti(H₂O)₆]²⁺DOption D. Δ\DeltaΔ^o of [Cr(H₂O)₆]²⁺ < [Mo(H₂O)₆]²⁺ and Δ\DeltaΔ^o of [Ti(H₂O)₆]³⁺ < [Ti(H₂O)₆]²⁺CheckSkip · show solution