Chemical Thermodynamics — JEE Main 2025 · 23 Jan, Morning shift · Q68

Question

Ice at -5° C is heated to become vapor with temperature of 110° C at atmospheric pressure. The entropy change associated with this process can be obtained from

Accepted Answer

(A) ∫ 268 K ^(273 K)(C p,m)/TdT+(Δ H m,fusion)/T f +(Δ H m,vaporisation)/T b +∫ 273 K ^(373 K)(C p,m dT)/T+∫ 373 K ^(383 K)(C p,m dT)/T

Answer

(B) ∫ 268 K ^(383 K)C p dT+(Δ H melting)/273+(Δ H boiling)/373

Answer

(C) ∫ 268 K ^(273 K)C p,m dT+(Δ H m,fusion)/T f +(Δ H m,vaporisation)/T b +∫ 273 K ^(373 K)C p,m dT+∫ 373 K ^(383 K)C p,m dT

Answer

(D) ∫ 268 K ^(383 K)C p dT+(q rev)/T

Chemical Thermodynamics: JEE Main 2025 Chemistry question

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Chemical Thermodynamics: JEE Main 2025 Chemistry question

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