Given that E^Θ O₂/H₂O = 1.23 V; E^Θ S₂O₈²⁻/SO₄²⁻ = 2.05 V E^Θ _ B r₂ /B r^ - = 1.09 V E^Θ _ A u³⁺ /Au = 1.4 V The strongest oxidizing agent is:

Redox Reactions and Electrochemistry: JEE Main 2019 Chemistry question

JEE Main 2019 · 8 Apr, Morning shift · Q989

JEE Main 20198 Apr, Morning shiftChemistryMediumRedox Reactions and Electrochemistry138× since 2002

Given that

{E^\Theta }_{{O_2}/{H_2}O} = 1.23\,V

;

{E^\Theta }_{{S_2}O_8^{2 - }/SO_4^{2 - }} = 2.05\,V

{E^\Theta }_{B{r_2}/B{r^ - }} = 1.09\,V

{E^\Theta }_{A{u^{3 + }}/Au} = 1.4\,V

The strongest oxidizing agent is :

JEE Main 2019 · 8 Apr, Morning shift · Q989

JEE Main 20198 Apr, Morning shiftChemistryMediumRedox Reactions and Electrochemistry138× since 2002

Given that

{E^\Theta }_{{O_2}/{H_2}O} = 1.23\,V

;

{E^\Theta }_{{S_2}O_8^{2 - }/SO_4^{2 - }} = 2.05\,V

{E^\Theta }_{B{r_2}/B{r^ - }} = 1.09\,V

{E^\Theta }_{A{u^{3 + }}/Au} = 1.4\,V

The strongest oxidizing agent is :