Given CO³⁺ + e^– → CO₂⁺; E^(o) = + 1.81 V Pb⁴⁺ + 2e^– → Pb₂⁺; E^(o) = + 1.67 V Ce⁴⁺ + e^– → Ce³⁺; E^(o) = + 1.61 V Bi³⁺ + 3e^– → Bi; E^(o) = + 0.20 V Oxidizing power of the species will increase in the order:

(D) Bi³⁺ < Ce⁴⁺ < Pb⁴⁺ < Co³⁺

(A) Co³⁺ < Ce⁴⁺ < Bi³⁺ < Pb⁴⁺

(B) Co³⁺ < Pb⁴⁺ < Ce⁴⁺ < Bi³⁺

(C) Ce⁴⁺ < Pb⁴⁺ < Bi³⁺ < Co³⁺

Redox Reactions and Electrochemistry: JEE Main 2019 Chemistry question

JEE Main 2019 · 12 Apr, Morning shift · Q986

JEE Main 201912 Apr, Morning shiftChemistryEasyRedox Reactions and Electrochemistry138× since 2002

Given CO³⁺ + e^–

\to

CO₂⁺ ; E^o = + 1.81 V Pb⁴⁺ + 2e^–

\to

Pb₂⁺ ; E^o = + 1.67 V Ce⁴⁺ + e^–

\to

Ce³⁺ ; E^o = + 1.61 V Bi³⁺ + 3e^–

\to

Bi ; E^o = + 0.20 V Oxidizing power of the species will increase in the order :

JEE Main 2019 Redox Reactions and Electrochemistry Question with Solution (12 Apr Morning shift, Q986) | JEE Arc