Hydrocarbons: JEE Main 2026 Chemistry question

Given below are two statements for the following reaction sequence. Compound 'X' (molecular formula $\mathrm{C_3H_6Cl_2}$) $\xrightarrow{\text{excess of }\mathrm{NaNH_2}}$ Compound 'Y'; Y $\xrightarrow{\text{dil. }\mathrm{H_2SO_4},\ \mathrm{Hg^{2+}}}$ Compound 'Z'; Y $\xrightarrow[\text{Red hot iron tube}]{\Delta}$ Compound 'Q' (Molecular formula $\mathrm{C_9H_{12}}$). Statement I: Compound 'Z' will give yellow precipitate with NaOI. Statement II: Compound 'Q' has two different types of 'H' atoms (aromatic : aliphatic) in the ratio 1:3. In the light of the above statements, choose the correct answer from the options given below: