For x R, x ≠ -1, if (1 + x)²⁰¹⁶ + x(1 + x)²⁰¹⁵ + x²(1 + x)²⁰¹⁴ +.... + x²⁰¹⁶ = Σ i = 0 ²⁰¹⁶ a i xⁱ, then a₁₇ is equal to:

Binomial Theorem and Its Simple Applications: JEE Main 2016 Mathematics question

JEE Main 2016 · 9 Apr, Morning shift · Q2910

JEE Main 20169 Apr, Morning shiftMathematicsMediumBinomial Theorem and Its Simple Applications131× since 2002

For x

\in

R, x

\ne

-1, if (1 + x)²⁰¹⁶ + x(1 + x)²⁰¹⁵ + x²(1 + x)²⁰¹⁴ + . . . . + x²⁰¹⁶ =

\sum\limits_{i = 0}^{2016} {{a_i}} \,{x^i},\,\,

then a₁₇ is equal to :