For x R, x ≠ 0, if y(x) is a differentiable function such that x ∫₁ˣ y (t) dt = (x + 1) ∫₁ˣ ty (t) dt, then y (x) equals: (where C is a constant.)

Integral Calculus: JEE Main 2016 Mathematics question

JEE Main 2016 · 10 Apr, Morning shift · Q3301

JEE Main 201610 Apr, Morning shiftMathematicsMediumIntegral Calculus369× since 2002

For x

\in

R, x

\ne

0, if y(x) is a differentiable function such that x

\int\limits_1^x y

(t) dt = (x + 1)

\int\limits_1^x ty

(t) dt, then y (x) equals : (where C is a constant.)