JEE Main 2016Session, Shift 1MathematicsMediumLimit, Continuity and Differentiability420× since 2002For x∈ R, f(x)=∣log2−sinx∣ x \in \,R,\,\,f\left( x \right) = \left| {\log 2 - \sin x} \right|\,\,x∈R,f(x)=∣log2−sinx∣ and g(x)=f(f(x)), \,\,g\left( x \right) = f\left( {f\left( x \right)} \right),\,\,g(x)=f(f(x)), then :AOption A. ggg is not differentiable at x=0x=0x=0BOption B. g′(0)=cos(log2)g'\left( 0 \right) = \cos \left( {\log 2} \right)g′(0)=cos(log2)COption C. g′(0)=−cos(log2)g'\left( 0 \right) = - \cos \left( {\log 2} \right)g′(0)=−cos(log2)DOption D. ggg is differentiable at x=0x=0x=0 and g′(0)=−sin(log2)g'\left( 0 \right) = - \sin \left( {\log 2} \right)g′(0)=−sin(log2)CheckSkip · show solution
