JEE Main 202124 Feb, Evening shiftMathematicsEasyLimit, Continuity and Differentiability420× since 2002For which of the following curves, the line x+3y=23x + \sqrt 3 y = 2\sqrt 3x+3y=23 is the tangent at the point (332,12)\left( {{{3\sqrt 3 } \over 2},{1 \over 2}} \right)(233,21)?AOption A. 2x2−18y2=92{x^2} - 18{y^2} = 92x2−18y2=9BOption B. y2=163x{y^2} = {1 \over {6\sqrt 3 }}xy2=631xCOption C. x2+9y2=9{x^2} + 9{y^2} = 9x2+9y2=9DOption D. x2+y2=7{x^2} + {y^2} = 7x2+y2=7CheckSkip · show solution
