For water at 100° C and 1 bar, Δ v ap H - Δ v ap U = _ _ _ _ _ _ _ × 10² J mol⁻¹. (Round off to the Nearest Integer) [Use: R = 8.31 J mol⁻¹ K⁻¹] [Assume volume of H₂O(l) is much smaller than volume of H₂O(g). Assume H₂O(g) treated as an ideal gas]

Chemical Thermodynamics: JEE Main 2021 Chemistry question

JEE Main 2021 · 27 Jul, Morning shift · Q23

JEE Main 202127 Jul, Morning shiftChemistryMediumChemical Thermodynamics84× since 2002

For water at 100

^\circ

C and 1 bar,

\Delta

_vap H

-

\Delta

_vap U = _____________

\times

10² J mol^

-

1. (Round off to the Nearest Integer) [Use : R = 8.31 J mol^

-

1 K^

-

1] [Assume volume of H₂O(l) is much smaller than volume of H₂O(g). Assume H₂O(g) treated as an ideal gas]

Your answerType your answer. Integers and decimals are accepted.

JEE Main 2021 Chemical Thermodynamics Question with Answer (27 Jul Morning shift, Q23) | JEE Arc