JEE Main 202429 Jan, Morning shiftChemistryHardEquilibrium123× since 2002For the reaction N2O4( g)⇄2NO2( g),Kp=0.492 atm\mathrm{N}_2 \mathrm{O}_{4(\mathrm{~g})} \rightleftarrows 2 \mathrm{NO}_{2(\mathrm{~g})}, \mathrm{K}_{\mathrm{p}}=0.492 \mathrm{~atm}N2O4( g)⇄2NO2( g),Kp=0.492 atm at 300 K.Kc300 \mathrm{~K} . \mathrm{K}_{\mathrm{c}}300 K.Kc for the reaction at same temperature is _________ ×10−2\times 10^{-2}×10−2. (Given : R=0.082 L atm mol−1 K−1\mathrm{R}=0.082 \mathrm{~L} \mathrm{~atm} \mathrm{~mol}^{-1} \mathrm{~K}^{-1}R=0.082 L atm mol−1 K−1)Your answerType your answer. Integers and decimals are accepted.CheckSkip · show solution
