Equilibrium: JEE Main 2021 Chemistry question

For the reaction $A(g) \rightleftharpoons B(g)$ at 495 K, $\Delta$_rG$^\circ$ = $-$9.478 kJ mol^$-$1. If we start the reaction in a closed container at 495 K with 22 millimoles of A, the amount of B in the equilibrium mixture is ____________ millimoles. (Round off to the Nearest Integer). [R = 8.314 J mol^$-$1 K^$-$1; ln 10 = 2.303]