For the reaction A → B, the rate constant k(in s⁻¹) is given by log ₁₀k = 20.35 - ((2.47 × 10³))/T The energy of activation in kJ mol⁻¹ is _ _ _ _ _ _. (Nearest integer) [Given: R = 8.314 J K⁻¹ mol⁻¹]

Chemical Kinetics: JEE Main 2021 Chemistry question

JEE Main 2021 · 31 Aug, Evening shift · Q3

JEE Main 202131 Aug, Evening shiftChemistryMediumChemical Kinetics62× since 2002

For the reaction A

\to

B, the rate constant k(in s^

-

1) is given by

{\log _{10}}k = 20.35 - {{(2.47 \times {{10}^3})} \over T}

The energy of activation in kJ mol^

-

1 is ____________. (Nearest integer) [Given : R = 8.314 J K^

-

1 mol^

-

Your answerType your answer. Integers and decimals are accepted.

JEE Main 2021 Chemical Kinetics Question with Answer (31 Aug Evening shift, Q3) | JEE Arc