JEE Main 20245 Apr, Evening shiftMathematicsHardSequence and Series179× since 2002For x⩾0x \geqslant 0x⩾0, the least value of K\mathrm{K}K, for which 41+x+41−x,K2,16x+16−x4^{1+x}+4^{1-x}, \frac{\mathrm{K}}{2}, 16^x+16^{-x}41+x+41−x,2K,16x+16−x are three consecutive terms of an A.P., is equal to :AOption A. 10BOption B. 4COption C. 8DOption D. 16CheckSkip · show solution
