JEE Main 202431 Jan, Morning shiftChemistryEasyEquilibrium123× since 2002For the given reaction, choose the correct expression of KC\mathrm{K}_{\mathrm{C}}KC from the following :- Fe(aq)3++SCN(aq)−⇌(FeSCN)(aq)2+\mathrm{Fe}_{(\mathrm{aq})}^{3+}+\mathrm{SCN}_{(\mathrm{aq})}^{-} \rightleftharpoons(\mathrm{FeSCN})_{(\mathrm{aq})}^{2+}Fe(aq)3++SCN(aq)−⇌(FeSCN)(aq)2+AOption A. KC=[Fe3+][SCN−][FeSCN2+]\mathrm{K}_{\mathrm{C}}=\frac{\left[\mathrm{Fe}^{3+}\right]\left[\mathrm{SCN}^{-}\right]}{\left[\mathrm{FeSCN}^{2+}\right]}KC=[FeSCN2+][Fe3+][SCN−]BOption B. KC=[FeSCN2+][Fe3+][SCN−]\mathrm{K}_{\mathrm{C}}=\frac{\left[\mathrm{FeSCN}^{2+}\right]}{\left[\mathrm{Fe}^{3+}\right]\left[\mathrm{SCN}^{-}\right]}KC=[Fe3+][SCN−][FeSCN2+]COption C. KC=[FeSCN2+]2[Fe3+][SCN−]\mathrm{K}_{\mathrm{C}}=\frac{\left[\mathrm{FeSCN}^{2+}\right]^2}{\left[\mathrm{Fe}^{3+}\right]\left[\mathrm{SCN}^{-}\right]}KC=[Fe3+][SCN−][FeSCN2+]2DOption D. KC=[FeSCN2+][Fe3+]2[SCN−]2\mathrm{K}_{\mathrm{C}}=\frac{\left[\mathrm{FeSCN}^{2+}\right]}{\left[\mathrm{Fe}^{3+}\right]^2\left[\mathrm{SCN}^{-}\right]^2}KC=[Fe3+]2[SCN−]2[FeSCN2+]CheckSkip · show solution
