JEE Main 20248 Apr, Morning shiftChemistryHardEquilibrium123× since 2002For the given hypothetical reactions, the equilibrium constants are as follows : X⇌Y;K1=1.0Y⇌Z;K2=2.0Z⇌W;K3=4.0\begin{aligned} & \mathrm{X} \rightleftharpoons \mathrm{Y} ; \mathrm{K}_1=1.0 \\ & \mathrm{Y} \rightleftharpoons \mathrm{Z} ; \mathrm{K}_2=2.0 \\ & \mathrm{Z} \rightleftharpoons \mathrm{W} ; \mathrm{K}_3=4.0 \end{aligned}X⇌Y;K1=1.0Y⇌Z;K2=2.0Z⇌W;K3=4.0 The equilibrium constant for the reaction X⇌W\mathrm{X} \rightleftharpoons \mathrm{W}X⇌W isAOption A. 12.0BOption B. 8.0COption C. 6.0DOption D. 7.0CheckSkip · show solution
