For the galvanic cell, Zn(s) + Cu²⁺ (0.02 M) → Zn²⁺ (0.04 M) + Cu(s), E c ell = _ _ _ _ _ _ _ × 10⁻² V. (Nearest integer) [Use: E_ Cu/C u²⁺ ⁰ = - 0.34 V, E_ Zn/Z n²⁺ ⁰ = + 0.76 V, 2.303RT/F = 0.059 V ]

Redox Reactions and Electrochemistry: JEE Main 2021 Chemistry question

JEE Main 2021 · 26 Aug, Evening shift · Q9

JEE Main 202126 Aug, Evening shiftChemistryMediumRedox Reactions and Electrochemistry138× since 2002

For the galvanic cell, Zn(s) + Cu²⁺ (0.02 M)

\to

Zn²⁺ (0.04 M) + Cu(s), E_cell = ______________

\times

10^

-

2 V. (Nearest integer) [Use :

E_{Cu/C{u^{2 + }}}^0

-

0.34 V,

E_{Zn/Z{n^{2 + }}}^0

= + 0.76 V,

{{2.303RT} \over F} = 0.059\,V

]

Your answerType your answer. Integers and decimals are accepted.