JEE Main 202313 Apr, Morning shiftMathematicsMediumLimit, Continuity and Differentiability420× since 2002For the differentiable function f:R−{0}→Rf: \mathbb{R}-\{0\} \rightarrow \mathbb{R}f:R−{0}→R, let 3f(x)+2f(1x)=1x−103 f(x)+2 f\left(\frac{1}{x}\right)=\frac{1}{x}-103f(x)+2f(x1)=x1−10, then ∣f(3)+f′(14)∣\left|f(3)+f^{\prime}\left(\frac{1}{4}\right)\right|f(3)+f′(41) is equal toAOption A. 13BOption B. 295\frac{29}{5}529COption C. 335\frac{33}{5}533DOption D. 7CheckSkip · show solution
