JEE Main 202227 Jul, Evening shiftMathematicsMediumLimit, Continuity and Differentiability420× since 2002For the curve C:(x2+y2−3)+(x2−y2−1)5=0C:\left(x^{2}+y^{2}-3\right)+\left(x^{2}-y^{2}-1\right)^{5}=0C:(x2+y2−3)+(x2−y2−1)5=0, the value of 3y′−y3y′′3 y^{\prime}-y^{3} y^{\prime \prime}3y′−y3y′′, at the point (α,α)(\alpha, \alpha)(α,α), α>0\alpha>0α>0, on C, is equal to ____________.Your answerType your answer. Integers and decimals are accepted.CheckSkip · show solution