JEE Main 20241 Feb, Morning shiftMathematicsHardCoordinate Geometry478× since 2002For 0<θ<π/20<\theta<\pi / 20<θ<π/2, if the eccentricity of the hyperbola x2−y2cosec2θ=5x^2-y^2 \operatorname{cosec}^2 \theta=5x2−y2cosec2θ=5 is 7\sqrt{7}7 times eccentricity of the ellipse x2cosec2θ+y2=5x^2 \operatorname{cosec}^2 \theta+y^2=5x2cosec2θ+y2=5, then the value of θ\thetaθ is :AOption A. π6\frac{\pi}{6}6πBOption B. 5π12\frac{5 \pi}{12}125πCOption C. π3\frac{\pi}{3}3πDOption D. π4\frac{\pi}{4}4πCheckSkip · show solution
