JEE Main 20236 Apr, Morning shiftChemistryMediumEquilibrium123× since 2002For a concentrated solution of a weak electrolyte (Keq =\mathrm{K}_{\text {eq }}=Keq = equilibrium constant) A2B3\mathrm{A}_{2} \mathrm{B}_{3}A2B3 of concentration 'ccc', the degree of dissociation 'α\alphaα' is :AOption A. (Keq25c2)15\left(\frac{K_{e q}}{25 c^{2}}\right)^{\frac{1}{5}}(25c2Keq)51BOption B. (Keq108c4)15\left(\frac{K_{e q}}{108 c^{4}}\right)^{\frac{1}{5}}(108c4Keq)51COption C. (Keq5c4)15\left(\frac{K_{e q}}{5 c^{4}}\right)^{\frac{1}{5}}(5c4Keq)51DOption D. (Keq6c5)15\left(\frac{K_{e q}}{6 c^{5}}\right)^{\frac{1}{5}}(6c5Keq)51CheckSkip · show solution
