JEE Main 202427 Jan, Evening shiftChemistryMediumChemical Thermodynamics84× since 2002For a certain thermochemical reaction M→N\mathrm{M} \rightarrow \mathrm{N}M→N at T=400 K,ΔH⊖=77.2 kJ mol−1,ΔS=122 JK−1,log\mathrm{T}=400 \mathrm{~K}, \Delta \mathrm{H}^{\ominus}=77.2 \mathrm{~kJ} \mathrm{~mol}^{-1}, \Delta \mathrm{S}=122 \mathrm{~JK}^{-1}, \logT=400 K,ΔH⊖=77.2 kJ mol−1,ΔS=122 JK−1,log equilibrium constant (logK)(\log K)(logK) is __________ ×10−1\times 10^{-1}×10−1.Your answerType your answer. Integers and decimals are accepted.CheckSkip · show solution