JEE Main 20199 Jan, Morning shiftMathematicsMediumCoordinate Geometry478× since 2002Equation of a common tangent to the circle, x² + y² – 6x = 0 and the parabola, y² = 4x is :AOption A. 232\sqrt 323y = 12x + 1BOption B. 3\sqrt 33y = x + 3COption C. 232\sqrt 323y = -x - 12DOption D. 3\sqrt 33y = 3x + 1CheckSkip · show solution