JEE Main 2011Annual, Paper 1MathematicsEasyLimit, Continuity and Differentiability420× since 2002d2xdy2{{{d^2}x} \over {d{y^2}}}dy2d2x equals:AOption A. −(d2ydx2)−1(dydx)−3- {\left( {{{{d^2}y} \over {d{x^2}}}} \right)^{ - 1}}{\left( {{{dy} \over {dx}}} \right)^{ - 3}}−(dx2d2y)−1(dxdy)−3BOption B. (d2ydx2)(dydx)−2{\left( {{{{d^2}y} \over {d{x^2}}}} \right)^{}}{\left( {{{dy} \over {dx}}} \right)^{ - 2}}(dx2d2y)(dxdy)−2COption C. −(d2ydx2)(dydx)−3- \left( {{{{d^2}y} \over {d{x^2}}}} \right){\left( {{{dy} \over {dx}}} \right)^{ - 3}}−(dx2d2y)(dxdy)−3DOption D. (d2ydx2)−1{\left( {{{{d^2}y} \over {d{x^2}}}} \right)^{ - 1}}(dx2d2y)−1CheckSkip · show solution
