JEE Main 202330 Jan, Morning shiftPhysicsEasyElectrostatics167× since 2002Electric field in a certain region is given by E→=(Ax2i^+By3j^). The SI unit of A and B\overrightarrow{\mathrm{E}}=\left(\frac{\mathrm{A}}{x^{2}} \hat{i}+\frac{\mathrm{B}}{y^{3}} \hat{j}\right) \text {. The } \mathrm{SI} \text { unit of } \mathrm{A} \text { and } \mathrm{B}E=(x2Ai^+y3Bj^). The SI unit of A and B are :AOption A. Nm2C;Nm3C\mathrm{Nm}^{2} \mathrm{C} ; \mathrm{Nm}^{3} \mathrm{C}Nm2C;Nm3CBOption B. Nm3C−1;Nm2C−1\mathrm{Nm}^{3} \mathrm{C}^{-1} ; \mathrm{Nm}^{2} \mathrm{C}^{-1}Nm3C−1;Nm2C−1COption C. Nm3C;Nm2C\mathrm{Nm}^{3} \mathrm{C} ; \mathrm{Nm}^{2} \mathrm{C}Nm3C;Nm2CDOption D. Nm2C−1;Nm3C−1\mathrm{Nm}^{2} \mathrm{C}^{-1} ; \mathrm{Nm}^{3} \mathrm{C}^{-1}Nm2C−1;Nm3C−1CheckSkip · show solution
