JEE Main 2002Annual, Paper 1MathematicsMediumComplex Numbers and Quadratic Equations264× since 2002Difference between the corresponding roots of x2+ax+b=0{x^2} + ax + b = 0x2+ax+b=0 and x2+bx+a=0{x^2} + bx + a = 0x2+bx+a=0 is same and a≠b,a \ne b,a=b, thenAOption A. a+b+4=0a + b + 4 = 0a+b+4=0BOption B. a+b−4=0a + b - 4 = 0a+b−4=0COption C. a−b−4=0a - b - 4 = 0a−b−4=0DOption D. a−b+4=0a - b + 4 = 0a−b+4=0CheckSkip · show solution