JEE Main 20244 Apr, Evening shiftPhysicsEasyGravitation159× since 2002Correct formula for height of a satellite from earths surface is :AOption A. (T2R2g4π2)1/3−R\left(\frac{T^2 R^2 g}{4 \pi^2}\right)^{1 / 3}-R(4π2T2R2g)1/3−RBOption B. (T2R2g4π)1/2−R\left(\frac{T^2 R^2 g}{4 \pi}\right)^{1 / 2}-R(4πT2R2g)1/2−RCOption C. (T2R2g4π2)−1/3+R\left(\frac{T^2 R^2 g}{4 \pi^2}\right)^{-1 / 3}+R(4π2T2R2g)−1/3+RDOption D. (T2R24π2g)1/3−R\left(\frac{T^2 R^2}{4 \pi^2 g}\right)^{1 / 3}-R(4π2gT2R2)1/3−RCheckSkip · show solution
