JEE Main 202329 Jan, Morning shiftMathematicsMediumMatrices and Determinants245× since 2002Consider the following system of equations αx+2y+z=1\alpha x+2y+z=1αx+2y+z=1 2αx+3y+z=12\alpha x+3y+z=12αx+3y+z=1 3x+αy+2z=β3x+\alpha y+2z=\beta3x+αy+2z=β for some α,β∈R\alpha,\beta\in \mathbb{R}α,β∈R. Then which of the following is NOT correct.AOption A. It has a solution for all α≠−1\alpha\ne-1α=−1 and β=2\beta=2β=2BOption B. It has no solution if α=−1\alpha=-1α=−1 and β≠2\beta\ne2β=2COption C. It has no solution for α=−1\alpha=-1α=−1 and for all β∈R\beta \in \mathbb{R}β∈RDOption D. It has no solution for α=3\alpha=3α=3 and for all β≠2\beta\ne2β=2CheckSkip · show solution
