Consider the following sequence of reactions. p-ethoxyaniline (CH₃CH₂O - C₆H₄-NH₂) (i) NaNO₂, HCl, 0-5^ (A) (i) phenol, NaOH; (ii) HCl dil. (B) (Molecular formula C₁₄H₁₄N₂O₂) (i) NaOH, (ii) H₃CCH₂Br (C) (Molecular formula C₁₆H₁₈N₂O₂). Total number of sp³ hybridised carbon atoms in the major product C formed is _ _ _.

Organic Compounds Containing Nitrogen: JEE Main 2025 Chemistry question

JEE Main 2025 · 23 Jan, Evening shift · Q71

JEE Main 202523 Jan, Evening shiftChemistryHardOrganic Compounds Containing Nitrogen35× since 2005

Consider the following sequence of reactions. p-ethoxyaniline (

\mathrm{CH_3CH_2O{-}C_6H_4{-}NH_2}

)

\xrightarrow{\text{(i) } \mathrm{NaNO_2, HCl}, 0\text{-}5^\circ\mathrm{C}}

(A)

\xrightarrow{\text{(i) phenol, NaOH; (ii) HCl dil.}}

(B) (Molecular formula

\mathrm{C_{14}H_{14}N_2O_2}

)

\xrightarrow{\text{(i) NaOH, (ii) } \mathrm{H_3CCH_2Br}}

\mathrm{C_{16}H_{18}N_2O_2}

). Total number of

sp^3

hybridised carbon atoms in the major product C formed is ______.

Your answerInteger or decimal

JEE Main 2025 Organic Compounds Containing Nitrogen Question with Solution (23 Jan Evening shift, Q71) | JEE Arc