Consider the following reduction processes: Zn²⁺ + 2e^– → Zn(s); E^(o) = – 0.76 V Ca²⁺ + 2e^– → Ca(s); E^(o) = –2.87 V Mg²⁺ + 2e^– → Mg(s); E^(o) = – 2.36 V Ni² + 2e^– → Ni(s); E^(o) = – 0.25 The reducing power of the metals increases in the order:

Redox Reactions and Electrochemistry: JEE Main 2019 Chemistry question

JEE Main 2019 · 10 Jan, Morning shift · Q993

JEE Main 201910 Jan, Morning shiftChemistryEasyRedox Reactions and Electrochemistry138× since 2002

Consider the following reduction processes : Zn²⁺ + 2e^–

\to

Zn(s) ; E^o = – 0.76 V Ca²⁺ + 2e^–

\to

Ca(s); E^o = –2.87 V Mg²⁺ + 2e^–

\to

Mg(s) ; E^o = – 2.36 V Ni² + 2e^–

\to

Ni(s) ; E^o = – 0.25 The reducing power of the metals increases in the order :

JEE Main 2019 Redox Reactions and Electrochemistry Question with Solution (10 Jan Morning shift, Q993) | JEE Arc