Consider the following lists: List-I (I) [-(2 π)/3, (2 π)/3]: cos x+ sin x=1 (II) [-(5 π)/18, (5 π)/18]: √(3) tan 3 x=1 (III) [-(6 π)/5, (6 π)/5]: 2 cos (2 x)=√(3) (IV) [-(7 π)/4, (7 π)/4]: sin x- cos x=1 List-II (P) has two elements (Q) has three elements (R) has four elements (S) has five elements (T) has six elements The correct option is:

(B) (I) → (P); (II) → (P); (III) → (T); (IV) → (R)

(A) (I) → (P); (II) → (S); (III) → (P); (IV) → (S)

(C) (I) → (Q); (II) → (P); (III) → (T); (IV) → (S)

(D) (I) → (Q); (II) → (S); (III) → (P); (IV) → (R)

Unclassified (maths): JEE Advanced 2022 Mathematics question

JEE Advanced 2022 · JEE Adv 2022 Paper 1, Paper 1 · Q15

JEE Advanced 2022JEE Adv 2022 Paper 1, Paper 1MathematicsHardUnclassified (maths)

Consider the following lists: List-I (I)

\left\{x \in\left[-\frac{2 \pi}{3}, \frac{2 \pi}{3}\right]: \cos x+\sin x=1\right\}

(II)

\left\{x \in\left[-\frac{5 \pi}{18}, \frac{5 \pi}{18}\right]: \sqrt{3} \tan 3 x=1\right\}

(III)

\left\{x \in\left[-\frac{6 \pi}{5}, \frac{6 \pi}{5}\right]: 2 \cos (2 x)=\sqrt{3}\right\}

(IV)

\left\{x \in\left[-\frac{7 \pi}{4}, \frac{7 \pi}{4}\right]: \sin x-\cos x=1\right\}

List-II (P) has two elements (Q) has three elements (R) has four elements (S) has five elements (T) has six elements The correct option is: