Equilibrium: JEE Main 2024 Chemistry question

Consider the dissociation of the weak acid HX as given below $\mathrm{HX}(\mathrm{aq}) \rightleftharpoons \mathrm{H}^{+}(\mathrm{aq})+\mathrm{X}^{-}(\mathrm{aq}), \mathrm{Ka}=1.2 \times 10^{-5}$ [$\mathrm{K}_{\mathrm{a}}$ : dissociation constant] The osmotic pressure of $0.03 \mathrm{M}$ aqueous solution of $\mathrm{HX}$ at $300 \mathrm{~K}$ is _________ $\times 10^{-2}$ bar (nearest integer). [Given : $\mathrm{R}=0.083 \mathrm{~L} \mathrm{~bar} \mathrm{~mol}^{-1} \mathrm{~K}^{-1}$]