JEE Main 202329 Jan, Evening shiftMathematicsMediumSets, Relations and Functions168× since 2002Consider a function f:N→Rf:\mathbb{N}\to\mathbb{R}f:N→R, satisfying f(1)+2f(2)+3f(3)+....+xf(x)=x(x+1)f(x);x≥2f(1)+2f(2)+3f(3)+....+xf(x)=x(x+1)f(x);x\ge2f(1)+2f(2)+3f(3)+....+xf(x)=x(x+1)f(x);x≥2 with f(1)=1f(1)=1f(1)=1. Then 1f(2022)+1f(2028)\frac{1}{f(2022)}+\frac{1}{f(2028)}f(2022)1+f(2028)1 is equal toAOption A. 8000BOption B. 8400COption C. 8100DOption D. 8200CheckSkip · show solution
