JEE Main 202229 Jun, Morning shiftChemistryMediumBiomolecules103× since 2002C₆H₁₂O₆ \buildrelZymase⟶\buildrel \text{Zymase} \over \longrightarrow⟶\buildrelZymase A ⟶ΔNaOI\mathrel{\mathop{\kern0pt\longrightarrow} \limits_\Delta ^\text{NaOI}}Δ⟶NaOI B + CHI₃ The number of carbon atoms present in the product B is _______________.Your answerType your answer. Integers and decimals are accepted.CheckSkip · show solution