JEE Main 202229 Jul, Evening shiftMathematicsHardSequence and Series179× since 2002 Let {an}n=0∞ be a sequence such that a0=a1=0 and an+2=3an+1−2an+1,∀n≥0.\begin{aligned} &\text { Let }\left\{a_{n}\right\}_{n=0}^{\infty} \text { be a sequence such that } a_{0}=a_{1}=0 \text { and } \\\\ &a_{n+2}=3 a_{n+1}-2 a_{n}+1, \forall n \geq 0 . \end{aligned} Let {an}n=0∞ be a sequence such that a0=a1=0 and an+2=3an+1−2an+1,∀n≥0. Then a25a23−2a25a22−2a23a24+4a22a24a_{25} a_{23}-2 a_{25} a_{22}-2 a_{23} a_{24}+4 a_{22} a_{24}a25a23−2a25a22−2a23a24+4a22a24 is equal toAOption A. 483BOption B. 528COption C. 575DOption D. 624CheckSkip · show solution
