At 298 ~K, the standard reduction potential for Cu²⁺ / Cu electrode is 0.34 ~V. Given: K sp Cu(OH)₂=1 × 10⁻²⁰ Take (2.303 RT)/F=0.059 ~V The reduction potential at pH=14 for the above couple is (-) x × 10⁻² ~V. The value of x is _ _ _ _ _ _

Redox Reactions and Electrochemistry: JEE Main 2023 Chemistry question

JEE Main 2023 · 13 Apr, Evening shift · Q8

JEE Main 202313 Apr, Evening shiftChemistryHardRedox Reactions and Electrochemistry138× since 2002

298 \mathrm{~K}

, the standard reduction potential for

\mathrm{Cu}^{2+} / \mathrm{Cu}

electrode is

0.34 \mathrm{~V}

. Given :

\mathrm{K}_{\mathrm{sp}} \mathrm{Cu}(\mathrm{OH})_{2}=1 \times 10^{-20}

Take

\frac{2.303 \mathrm{RT}}{\mathrm{F}}=0.059 \mathrm{~V}

The reduction potential at

\mathrm{pH}=14

for the above couple is

(-) x \times 10^{-2} \mathrm{~V}

. The value of

x

is ___________

Your answerType your answer. Integers and decimals are accepted.